How do you solve $6 n^{0} \cdot n^{0}$ $6n ^ { 0} \cdot n ^ { 0}$ ?

Question

1500 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-27T01:47:44

Change $n^{0}$ $n^0$ to one and multiply

Any number to the zero power is equal to one. so

$n^{0} = 1$ $n^0 = 1$

so substituting 1 for $n^{o}$ $n^o$ gives

$6 \times 1 \times 1 = 6$ $6 xx 1 xx 1 = 6$

How do you solve 6n0⋅n06n ^ { 0} \cdot n ^ { 0}?