How do you solve $6n^2-19n+15=0$ ?

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Answer 1 · 2016-05-19T15:37:56

The solutions for the expression are:
$n = 5/3$

$n = 3/2$

$6n^2 - 19n + 15 = 0$

The equation is of the form $color(blue)(an^2+bn+c=0$ where:
$a=6, b=-19, c=15$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (-19)^2-(4* 6 * 15)$

$= 361 - 360= 1$

The solutions are found using the formula
$n=(-b+-sqrtDelta)/(2*a)$

$n = (-(-19)+-sqrt(1))/(2*6) = (19+-1)/12$

$n = (19+1) /12 = 20/12 = 5/3$

$n = (19-1) /12 = 18/12 = 3/2$

How do you solve 6n^2-19n+15=06n^2-19n+15=0?