How do you solve -6x+14<-28 or 9x+15<-12?

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Answer 1 · 2017-06-20T01:47:24

$(-oo,-3) uu (7,oo)$

Solve each inequality separately, then combine them with the "or" operator, and then simplify if possible.

Let's start with the first inequality:

$-6x+14 < -28$

$-6x < -42$

$6x > 42$

$x > 7$

Now, we solve the second inequality:

$9x+15 < -12$

$9x < -27$

$x < -3$

Combining the two, we get:

$x < -3 or x > 7$

This cannot be simplified, since the two solution regions do not overlap. The more formal way to write this (with interval notation) is:

$(-oo,-3) uu (7,oo)$

On a number line, the solution set looks like this:

Wolfram Alpha

Final Answer