How do you solve $6x^2 - 11x + 2 = 0$ by factoring?

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Answer 1 · 2015-08-16T00:32:50

Factor y = 6x^2 - 11x + 2 = 0

D = b^2 - 4ac = 121 - 48 = 73. Since 73 is not a perfect square, this trinomial can't be factored.

How do you solve 6x^2 - 11x + 2 = 06x^2 - 11x + 2 = 0 by factoring?