How do you solve $6 x^{2} = 17 x - 12$ $6x^2=17x-12$ ?

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How do you solve $6 x^{2} = 17 x - 12$ $6x^2=17x-12$ ?

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Answer 1 · 2016-06-15T09:33:21

$(3 x - 4) (2 x - 3)$ $(3x-4)(2x-3)$

Explanation:

As soon as you see an $x^{2}$ $x^2$ term, it is a quadratic equation and it has to be made equal to 0.

$6 x^{2} - 17 x + 12 = 0$ $6x^2 -17x+12 = 0$

Find factors of 6 and 12 which add to 17.

We find factors of 6 and 12 and cross multiply
$34 \Rightarrow 2 \times 4 = 8$ $3" " 4 rArr 2 xx 4 = 8$
$23 \Rightarrow 3 \times 3 = 98 + 9 = 17$ $2" " 3 rArr 3 xx 3= 9 " " 8 + 9 = 17$

The signs in the brackets will be the same, (because of the + with the 12, they will both be -, (because of the sign with -17).

$(3 x - 4) (2 x - 3)$ $(3x-4)(2x-3)$

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How do you solve $6 x^{2} = 17 x - 12$ $6x^2=17x-12$ ?

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How do you solve $6 x^{2} = 17 x - 12$ $6x^2=17x-12$ ?