How do you solve 6x^2=17x-12?

1 Answer
Jun 15, 2016

(3x-4)(2x-3)

Explanation:

As soon as you see an x^2 term, it is a quadratic equation and it has to be made equal to 0.

6x^2 -17x+12 = 0

Find factors of 6 and 12 which add to 17.

We find factors of 6 and 12 and cross multiply
3" " 4 rArr 2 xx 4 = 8
2" " 3 rArr 3 xx 3= 9 " " 8 + 9 = 17

The signs in the brackets will be the same, (because of the + with the 12, they will both be -, (because of the sign with -17).

(3x-4)(2x-3)