Question

How do you solve `6x^2 + 36x + 18 = 0` using completing the square?

Answer 1

First thing to notice, is that everything can be divided by 6

Explanation:

So the equation becomes:
`x^2+6x+3=0`

Completing the square is you take half of the number with `x` and square it, which would be `x^2+6x+9`, but to even out with the `3` you've got, you write `3=9-6`:
`x^2+6x+9-6=0->`
`(x+3)^2-6=0->(x+3)^2=6->`
`x+3=+-sqrt6->x=-3+-sqrt6`