How do you solve $6 x^{2} + 84 x + 300 = 0$ $6x^2+84x+300=0$ by completing the square?

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How do you solve $6 x^{2} + 84 x + 300 = 0$ $6x^2+84x+300=0$ by completing the square?

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Answer 1 · 2016-07-24T19:27:14

$x = - 7 \pm \sqrt{-} 1$ $x=-7+-sqrt-1$

Explanation:

$6 x^{2} + 84 x + 300 = 0$ $6x^2+84x+300=0$
Dividing bothe the sides by $6$ $6$ we get
$x^{2} + 14 x + 50 = 0$ $x^2+14x+50=0$
or
$x^{2} + 2 x (7) + 49 + 1 = 0$ $x^2+2x(7)+49+1=0$
or
$x^{2} + 2 x (7) + 49 = - 1$ $x^2+2x(7)+49=-1$
or
$x^{2} + 2 x (7) + 7^{2} = - 1$ $x^2+2x(7)+7^2=-1$
or
${(x + 7)}^{2} = - 1$ $(x+7)^2=-1$
or
$x + 7 = \pm \sqrt{-} 1$ $x+7=+-sqrt-1$
or
$x = - 7 \pm \sqrt{-} 1$ $x=-7+-sqrt-1$

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How do you solve $6 x^{2} + 84 x + 300 = 0$ $6x^2+84x+300=0$ by completing the square?

1 Answer

Explanation:

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How do you solve 6x2+84x+300=06x^2+84x+300=0 by completing the square?

1 Answer

Explanation:

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How do you solve $6 x^{2} + 84 x + 300 = 0$ $6x^2+84x+300=0$ by completing the square?