How do you solve $6x^2 + 8x = 14$ ?

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Answer 1 · 2015-09-09T12:52:00

This equation has 2 real solutions: $x_1=-2 1/3$ and $x_2=1$

Before further calculations you have to move $14$ to the left:

$6x^2+8x-14=0$

Now you can divide both sides by $2$ :

$3x^2+4x-7=0$

Now you can calculate the discriminant:

$Delta=4^2-4*3*(-7)=16+84=100$
$sqrt(Delta)=10$

$x_1=(-b-sqrt(Delta))/(2*a)=(-4-10)/(2*3)=-14/6=-2 1/3$

$x_2=(-b+sqrt(Delta))/(2*a)=(-4+10)/(2*3)=6/6=1$

How do you solve 6x^2 + 8x = 146x^2 + 8x = 14?