How do you solve $7 (8 - 8 b) = - 112$ $7( 8- 8b ) = - 112$ ?

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Answer 1 · 2018-06-13T00:36:16

$b = 3$ $b = 3$

$7 (8 - 8 b) = - 112$ $7(8-8b) = -112$

First, use the distributive property (shown below) to simplify $7 (8 - 8 b)$ $7(8-8b)$ :
cdn.virtualnerd.com

Following this image, we know that:
$7 (8 - 8 b) = (7 \cdot 8) + (7 \cdot - 8 b) = 56 - 56 b$ $color(blue)(7(8-8b) = (7 * 8) + (7 * -8b) = 56 - 56b)$

Put that back into the equation:
$56 - 56 b = - 112$ $56 - 56b = -112$

Now subtract $56$ $color(blue)(56)$ from both sides of the equation:
$56 - 56b quadcolor(blue)(-quad56) = -112 quadcolor(blue)(-quad56)$

$-56b = -168$

Divide both sides by $color(blue)(-56)$ :
$(-56b)/color(blue)(-56) = (-168)/color(blue)(-56)$

Therefore,
$b = 3$

Hope this helps!

How do you solve 7( 8- 8b ) = - 1127(8−8b)=−1127( 8- 8b ) = - 112?