How do you solve $7 \frac{3}{7} + 5 \frac{2}{3}$ $7\frac { 3} { 7}+ 5\frac { 2} { 3}$ ?

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Answer 1 · 2018-03-18T13:32:29

See a solution process below:

First, rewrite the expression as:

$(7 + \frac{3}{7}) + (5 + \frac{2}{3}) \Rightarrow$ $(7 + 3/7) + (5 + 2/3) =>$

$7 + \frac{3}{7} + 5 + \frac{2}{3} \Rightarrow$ $7 + 3/7 + 5 + 2/3 =>$

$7 + 5 + \frac{3}{7} + \frac{2}{3} \Rightarrow$ $7 + 5 + 3/7 + 2/3 =>$

$12 + \frac{3}{7} + \frac{2}{3}$ $12 + 3/7 + 2/3$

To add the fractions we must put them over a common denominator by multiplying each fraction by the appropriate form of $1$ $1$ :

$12 + (\frac{3}{3} \times \frac{3}{7}) + (\frac{7}{7} \times \frac{2}{3}) \Rightarrow$ $12 + (3/3 xx 3/7) + (7/7 xx 2/3) =>$

$12 + \frac{3 \times 3}{3 \times 7} + \frac{7 \times 2}{7 \times 3} \Rightarrow$ $12 + (3 xx 3)/(3 xx 7) + (7 xx 2)/(7 xx 3) =>$

$12 + \frac{9}{21} + \frac{14}{21} \Rightarrow$ $12 + 9/21 + 14/21 =>$

$12 + \frac{9 + 14}{21} \Rightarrow$ $12 + (9 + 14)/21 =>$

$12 + \frac{23}{21}$ $12 + 23/21$

Now, we can convert the improper fraction to a mixed number:

$12 + \frac{21 + 2}{21} \Rightarrow$ $12 + (21 + 2)/21 =>$

$12 + \frac{21}{21} + \frac{2}{21} \Rightarrow$ $12 + 21/21 + 2/21 =>$

$12 + 1 + \frac{2}{21} \Rightarrow$ $12 + 1 + 2/21 =>$

$13 + \frac{2}{21} \Rightarrow$ $13 + 2/21 =>$

$13 \frac{2}{21}$ $13 2/21$

How do you solve 7\frac { 3} { 7}+ 5\frac { 2} { 3}737+5237\frac { 3} { 7}+ 5\frac { 2} { 3}?