How do you solve $7^x=49$ ?

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Answer 1 · 2016-09-30T01:13:43

$x=2$

$7^x=49$
$=> 7^x=7^2$
$=> x=2$

Answer 2 · 2016-09-30T01:20:56

$x=2$

By observation we can see that $x=2$ because $7^2=49$ . But let's solve this another way. We can do it using logs.

$7^x=49$

$log7^x=log49$

$xlog7=log(7xx7)$

$x=log(7xx7)/log7$

$x=(log7+log7)/log7$

$x=log7/log7+log7/log7=1+1=2$

How do you solve 7^x=497^x=49?