How do you solve $72-26y=2y^2$ by factoring?

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Answer 1 · 2015-03-27T06:30:53

Do a little regrouping

$72−26y=2y^2$

$=-2y^2 +72 - 26 y = 0$

$=(y^2 - 13 y + 36 )= 0/-2= 0$

$= (y−4)(y−9)=0$

Hence possible Solutions are y = 4 , y = 9

How do you solve 72-26y=2y^272-26y=2y^2 by factoring?