Question

How do you solve `7x^2 +28=53x`?

Answer 1

`x = 4/7`; `x = 7`

Explanation:

subtract `53x` from both sides
`7x^2 -53x +28 = 0`
factor
`(7x - 4)(x - 7) = 0`
use zero product property
`7x - 4 = 0` or `x - 7 = 0`
solve each equation
`x = 4/7` or `x = 7`