How do you solve $8- 3r \leq 5- 2r$ ?

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Answer 1 · 2016-12-14T14:08:39

$r >= 3$

First, do the necessary arithmetic to isolate the $r$ term on one side of the inequality and the constants on the other side of the inequality:

$8 - 3r + 3r - 5 <= 5 - 5 - 2r + 3r$

$8 - 0 - 5 <= 0 - 2r + 3r$

$8 - 5<= r$

$3 <= r$

To get this solution in terms of $r$ we need to reverse or "flip" the inequality:

$r >= 3$

How do you solve 8- 3r \leq 5- 2r8- 3r \leq 5- 2r?