How do you solve #-8<3x+4<22#?

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Answer 1 · 2017-01-21T14:25:33

The answer is #-4 < x <6#

#-8<3x+4<22#

subtract 4 on all sides

#-8color(red)(-4)<3x+4color(red)(-4)<22color(red)(-4)#

#-12<3x<18#

Divide by 3

#-12/color(blue)(3)<3x/color(blue)(3)<18/color(blue)(3)#

#-4 < x <6#