How do you solve $8^(-5a)-5=53$ ?

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Answer 1 · 2016-10-07T17:32:43

$a=-0.391$

$8^(-5a)-5=53$

$hArr8^(-5a)=53+5=58$

ot $log_8(58)=-5a$

or $a=-1/5xxlog_8(58)=-1/5xxlog58/log8$

i.e. $a=-1/5xx1.763428/0.90309=-0.391$

How do you solve 8^(-5a)-5=538^(-5a)-5=53?