How do you solve $8 - (- n) = 1$ $8-(-n)=1$ ?

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How do you solve $8 - (- n) = 1$ $8-(-n)=1$ ?

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Answer 1 · 2017-09-28T21:06:13

$n = - 7$ $n=-7$

Explanation:

Removing the bracket,
We get
$8 + n = 1$ $8+n=1$ as $(-) \cdot (-)$ $(-)*(-)$ is $+$ $+$
$n = 1 - 8 = - 7$ $n=1-8=-7$ since +8 is moved from Left Hand Side(L.H.S.) to R.H.S, it bemes -8

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How do you solve $8 - (- n) = 1$ $8-(-n)=1$ ?

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