How do you solve $8(x+4)^2=9$ ?

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Answer 1 · 2016-07-23T14:11:57

$x = -2.939 " or " x = -5.061$

Do not be tempted to multiply it all out and make equal to 0.

$8(x+4)^2 = 9" divide by 8"$

$(x+4)^2 = 9/8" square root both sides"$ t8#

$x+4 = +-sqrt(9/8)$

$x = +3/sqrt8 -4 " or "x = -3/sqrt8-4$

$x = -2.939 " or " x = -5.061$

How do you solve 8(x+4)^2=98(x+4)^2=9?