How do you solve $-8e^(-p)=-49$ ?

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Answer 1 · 2018-06-20T16:05:18

$p = log(8/49)$

Divide both sides by $-8$ :

$e^{-p} = 49/8$

consider logarithm of both sides:

$log(e^{-p}) = log(49/8)$

since $log(e^s) = s$ , we have

$-p = log(49/8)$

and thus

$p = -log(49/8) = log(8/49)$

How do you solve -8e^(-p)=-49-8e^(-p)=-49?