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How do you solve $8 u^{2} - 2 u = 0$ $8u^2-2u=0$ ?

1 Answer

Jun 7, 2018

$u = 0$ $u=0$

$u = \frac{1}{2}$ $u=1/2$

Explanation:

$8 u^{2} - 2 u = 0$ $8u^2-2u=0$

factor:

$2 u (4 u - 2) = 0$ $2u(4u-2) = 0$

$2 u = 0$ $2u = 0$

$u = 0$ $u=0$

or

$4 u - 2 = 0$ $4u-2=0$

$u = \frac{1}{2}$ $u=1/2$

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