How do you solve $| 8 x - 48 | = 0$ $|8x-48|=0$ ?

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Answer 1 · 2016-06-12T07:55:03

$x = 6$ $x=6$

If $| a | = 0$ $|a|=0$ , we only have $a = 0$ $a=0$

Hence for $| 8 x - 48 | = 0$ $|8x-48|=0$

$8 x - 48 = 0$ $8x-48=0$

or $8 x = 48$ $8x=48$

or $x = \frac{48}{8} = 6$ $x=48/8=6$

How do you solve |8x−48|=0 |8x-48|=0 ?