How do you solve #8x=-72#?

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Answer 1 · 2018-03-10T02:36:01

See a solution process below:

Divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equation balanced:

#(8x)/color(red)(8) = -72/color(red)(8)#

#(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = -(8 xx 9)/color(red)(8)#

#x = -(color(red)(cancel(color(black)(8))) xx 9)/cancel(color(red)(8))#

#x = -9#

Answer 2 · 2018-03-10T02:38:01

#x = -9#

All we have to do to solve this equation is isolate #x# by itself on one side of the equals sign.

To do that, divide each side by #8#, and then #x# will be isolated, revealing the answer:
#8x=−72#

#(8x)/color(blue)8=(−72)/color(blue)8#

#(cancel(8)x)/cancel(color(blue)8)=(−72)/color(blue)8#

#x=(−72)/8#

#x=−9#