How do you solve 9*9^(10k-2.7)=339910k2.7=33?

1 Answer
Aug 3, 2016

k = 0.33k=0.33 to 2 dp

Explanation:

Remember how we multiply exponents:

x^a*x^b = x^(a+b)xaxb=xa+b

We have 9^1*9^(10k-2.7) = 3391910k2.7=33

therefore 9^(10k-1.7) = 33

Take natural logs of both sides and use rules of logs to bring exponent down.

(10k-1.7)ln(9) = ln(33)

10k-1.7 = (ln(33))/(ln(9))

k = 1/10((ln(33))/(ln(9)) + 1.7)

k = 0.33 to 2 dp