How do you solve −9⋅e3−6r=−3?

1 Answer
Gió
Oct 8, 2016

I found: r=16{3−ln[13]}=0,6831

Explanation:

Let us try rearranging it:
e3−6r=−3−9
I took the −9 to the right:
we get:
e3−6r=13
Take the natural log of both sides:
ln[e3−6r]=ln[13]
we get:
3−6r=ln[13]
6r=3−ln[13]
r=16{3−ln[13]}
if you can use a scientific calculator you'd get:
r=16{3−ln[13]}=0,6831

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