How do you solve $9^{x - 4} = 7.13$ $9^(x-4)=7.13$ ?

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Answer 1 · 2018-04-01T13:03:17

Solution: $x \approx 4.894$ $x~~ 4.894$

$9^{x - 4} = 7.13$ $9^(x-4)=7.13$ . Taking natural log on both sides we get,

$(x - 4) ln 9 = ln 7.13$ $(x-4)ln 9 = ln 7.13$

$:. (x-4) = ln 7.13/ln 9$ or

$(x-4) ~~ 0.894:. x~~ 4+0.894~~ 4.894$

Solution: $x~~ 4.894$ [Ans]

How do you solve 9^(x-4)=7.139x−4=7.139^(x-4)=7.13?