Question

How do you solve `92- 42x = 2x^2`?

Answer 1

`x = 2 or x = -23`

Explanation:

Notice that it is a quadratic equation because there is an `x^2` term. The first step is to move all the terms to one side to make the equation equal to `0`

`2x^2 +42x-92=0" "larr div 2`

`x^2 +21x-46=0" "larr` find factors if possible

`(x+23)(x-2)=0`

Either factor could be equal to `0`

`x+23 = 0 " "rarr x =-23`

`x-2=0" "rarr x = 2`