How do you solve $(9w+11)(w +9)=79$ ?

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Answer 1 · 2016-11-12T00:25:52

The two answers are:
$w=-2/9$
$w=-10$

$(9w+11)(w+9)=79$

In order to make a quadratic equation where one side equals zero, first multiply out, or FOIL, the left side:
$9w^2+81w+11w+99=79$

Simplify by combining like terms, and setting one side equal to zero.
$9w^2+92w+20=0$

Solve by factoring:
$9w^2+90w+2w+20=0$

$9w(w+10)+2(w+10)=0$

$(9w+2)(w+10)=0$

$w=-2/9$
$w=-10$

How do you solve (9w+11)(w +9)=79(9w+11)(w +9)=79?