How do you solve 9x^2 - 21x + 10 = 0?

1 Answer
Alan P.
Jun 13, 2015

By factoring the left side we can get x=5/3 or x= 2/3

Explanation:

Given 9x^2-21x+10
the left side can be factored to give
color(white)("XXXX")(3x-5)(3x-2)=0
which implies either
color(white)("XXXX")3x-5 = 0 rArr x = 5/3
or
color(white)("XXXX")3x-2 =0 rArr x=2/3

Related questions
See all questions in Comparing Methods for Solving Quadratics
Impact of this question
2778 views around the world
You can reuse this answer
Creative Commons License