How do you solve $9 x^{2} + 342 x + 3230 = 0$ $9x^2+342x+3230=0$ by completing the square?

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Answer 1 · 2016-06-27T18:24:11

$x = - 19 \pm \frac{\sqrt{19}}{3}$ $x= - 19 pm sqrt(19)/3$

$9 x^{2} + 342 x + 3230 = 0$ $9x^2+342x+3230=0$

$x^{2} + 38 x + \frac{3230}{9} = 0$ $x^2+38x+3230/9=0$

${(x + 19)}^{2} - 19^{2} + \frac{3230}{9} = 0$ $(x+19)^2 - 19^2+3230/9=0$
$= {(x + 19)}^{2} - \frac{19}{9} = 0$ $= (x+19)^2 - 19/9=0$

${(x + 19)}^{2} = \frac{19}{9}$ $(x+19)^2 = 19/9$

$(x + 19) = \pm \sqrt{\frac{19}{9}} = \pm \frac{\sqrt{19}}{3}$ $(x+19) = pm sqrt(19/9) = pm sqrt(19)/3$

$x = - 19 \pm \frac{\sqrt{19}}{3}$ $x= - 19 pm sqrt(19)/3$

How do you solve 9x^2+342x+3230=0 9x2+342x+3230=09x^2+342x+3230=0 by completing the square?