How do you solve $9x^2 = x^3$ ?

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Answer 1 · 2016-05-18T04:51:04

$x=0$
$x=9$

Given -

$9x^2=x^3$
$9x^2-x^3=0$
$x^2(9-x)=0$
$x^2=0$
$x=0$
$9-x=0$
$x=9$

Answer 2 · 2016-05-19T03:06:30

$=> x = 0 or 9$

While most people would straightaway cancel the $x^2$ on both sides .I would find that rather foolish.

This is an important concept to have not to cancel x terms on either side of the equation but to bring everything over to one side

$9x^2 = x^3$

$9x^2 -x^3 = 0$

$x^2(9 -x) = 0$

$=> x^2 = 0 or 9-x = 0$

$=> x = +-0 or x = 9$

So we get our 3 solutions out of which 2 are not distinct roots