How do you solve #9x-8=x^2#?
1 Answer
May 2, 2018
Explanation:
#"express the equation in "color(blue)"standard form"#
#•color(white)(x)ax^2+bx+c=0#
#"subtract "9x-8" from both sides"#
#rArrx^2-9x+8=0larrcolor(blue)"in standard form"#
#"the factors of + 8 which sum to - 9 are - 1 and - 8"#
#rArr(x-1)(x-8)=0#
#"equate each factor to zero and solve for x"#
#x-1=0rArrx=1#
#x-8=0rArrx=8#