How do you solve $(a + 1) (a + 2) = 0$ $(a+1)(a+2) = 0$ by factoring?

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Answer 1 · 2015-08-17T06:31:44

The solutions are
$a = - 1, a = - 2$ $color(blue)(a=-1,a=-2$

$(a + 1) (a + 2) = 0$ $(a+1)(a+2)=0$ is already the factorised form of the equation
$a^{2} + 3 a + 2$ $a^2+3a+2$

Since we have the factorised form we simply equate the factors to the number on the R.H.S and obtain the solutions.

$(a + 1) (a + 2) = 0$ $(a+1)(a+2)=0$

Solution 1:
$a + 1 = 0, a = - 1$ $a+1=0, color(blue)(a=-1$

Solution 2
$a + 2 = 0, a = - 2$ $a+2=0, color(blue)(a=-2$

How do you solve (a+1)(a+2)=0(a+1)(a+2) = 0 by factoring?