How do you solve $(a+1)(a+2) = 0$ by factoring?

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Answer 1 · 2015-08-17T06:31:44

The solutions are
$color(blue)(a=-1,a=-2$

$(a+1)(a+2)=0$ is already the factorised form of the equation
$a^2+3a+2$

Since we have the factorised form we simply equate the factors to the number on the R.H.S and obtain the solutions.

$(a+1)(a+2)=0$

Solution 1:
$a+1=0, color(blue)(a=-1$

Solution 2
$a+2=0, color(blue)(a=-2$

How do you solve (a+1)(a+2) = 0(a+1)(a+2) = 0 by factoring?