How do you solve $a^2-2a-24=0$ ?

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Answer 1 · 2015-07-15T21:02:37

First you factorise

You find two numbers that have $24$ as a product, with a difference (because of the $-$ sign) of $2$ .
After some trying you will find $4and6$ :

$(a-6)(a+4)=0->a=6ora=-4$

How do you solve a^2-2a-24=0a^2-2a-24=0?