How do you solve $A=h/2(a+b)$ for h?

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Answer 1 · 2018-03-05T15:06:02

See a solution process below:

First, multiply each side of the equation by $color(red)(2)$ to eliminate the fraction while keeping the equation balanced:

$color(red)(2) xx A= color(red)(2) xx h/2(a + b)$

$2A = cancel(color(red)(2)) xx h/color(red)(cancel(color(black)(2)))(a + b)$

$2A = h(a + b)$

Now, divide each side of the equation by $color(red)(a + b)$ to solve for $h$ while keeping the equation balanced:

$(2A)/color(red)(a + b) = (h(a + b))/color(red)(a + b)$

$(2A)/(a + b) = (hcolor(red)(cancel(color(black)((a + b)))))/cancel(color(red)(a + b))$

$(2A)/(a + b) = h$

$h = (2A)/(a + b)$

How do you solve A=h/2(a+b)A=h/2(a+b) for h?