How do you solve abs(10+x)<=13|10+x|13?

1 Answer
Apr 15, 2017

-23<=x<=323x3

Explanation:

Inequalities of the type |x|<=a|x|a always have solutions of the form.

-a<=x<=aaxa

rArr-13<=10+x<=131310+x13

Isolate x in the centre interval by subtracting 10 from ALL 3 intervals.

-13-10<=cancel(10)cancel(-10)+x<=13-10

rArr-23<=x<=3" is the solution"