How do you solve abs(10+x)<=13|10+x|≤13?
1 Answer
Apr 15, 2017
Explanation:
Inequalities of the type
|x|<=a|x|≤a always have solutions of the form.
-a<=x<=a−a≤x≤a
rArr-13<=10+x<=13⇒−13≤10+x≤13 Isolate x in the centre interval by subtracting 10 from ALL 3 intervals.
-13-10<=cancel(10)cancel(-10)+x<=13-10
rArr-23<=x<=3" is the solution"