How do you solve abs(10+x)<=13|10+x|≤13?

1 Answer
Jim G.
Apr 15, 2017

-23<=x<=3−23≤x≤3

Explanation:

Inequalities of the type |x|<=a|x|≤a always have solutions of the form.

-a<=x<=a−a≤x≤a

rArr-13<=10+x<=13⇒−13≤10+x≤13

Isolate x in the centre interval by subtracting 10 from ALL 3 intervals.

-13-10<=cancel(10)cancel(-10)+x<=13-10

rArr-23<=x<=3" is the solution"

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