How do you solve #abs(11+2x)=5#?
1 Answer
May 23, 2018
Explanation:
#"the expression inside the absolute value bars can be"#
#"positive or negative hence there are 2 possible solutions"#
#color(magenta)"positive expression"#
#11+2x=5#
#"subtract 11 from both sides and divide by 2"#
#2x=5-11=-6rArrx=(-6)/2=-3#
#color(magenta)"negative expression"#
#-(11+2x)=5larr"distribute"#
#-11-2x=5#
#"add 11 to both sides and divide by "-2#
#-2x=5+11=16rArrx=16/(-2)=-8#
#color(blue)"As a check"# Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
#x=-3to|11-6|=|5|=5#
#x=-8to|11-16|=|-5|=5#
#x=-8" or "x=-3" are the solutions"#