How do you solve abs(3x + 2) - 1 >=10?

1 Answer
Nghi N.
Jul 11, 2016

x <= -13/3
x >= 3

Explanation:

I3x + 2I >= 11
Separate solving into 2 parts:
a.(3x + 2) >= 11
3x >= 9@ x >= 3 b. -(3x + 2) >= 11 - 3x - 2 >= 11 - 3x >= 13 x <= -13/3 Note. The 2 end points (-13/3)# and (3) are included in the solution set.
Graph:

=============== -13/3 ---------0---------- 3 =============

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