How do you solve $abs((3x+2)/2)=abs((2x-3)/3)$ ?

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Answer 1 · 2017-07-08T21:57:35

$x in {0 , -12/5}$

$(3x + 2)/2 = (2x - 3)/3 or (3x + 2)/2 = -(2x - 3)/3$

$9x + 6 = 4x - 6 or 9x + 6 = -4x + 6$

$5x = -12 or 13x = 0$

$x = -12/5 or x = 0$

How do you solve abs((3x+2)/2)=abs((2x-3)/3)abs((3x+2)/2)=abs((2x-3)/3)?