How do you solve $abs( 4 - 2/7x )+ 2 = 14$ ?

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Answer 1 · 2015-09-01T13:01:28

$color(green)( x = -28 or x = 56$

$abs( 4 - 2/7x )+ 2 = 14$

Transposing $2$ to the other side, we get:

$abs( 4 - 2/7x ) = 14 - 2$

$abs( 4 - 2/7x ) = 12$

This implies that :

$4 - 2/7x = 12 or 4 - 2/7x = -12$

$- 2/7x = 12 - 4 or - 2/7x = -12 - 4$

$- 2/7x = 8 or - 2/7x = -16$

Multiplying both equations with $-7/2$ , we get:

$x = 8*(-7/2) or x = -16*(-7/2)$

$color(green)( x = -28 or x = 56$

How do you solve abs( 4 - 2/7x )+ 2 = 14abs( 4 - 2/7x )+ 2 = 14?