How do you solve $abs(4/3x+7)+5=14$ ?

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Answer 1 · 2015-03-30T14:20:50

Remembering that:

$|f(x)|=n$ ( $n$ positive number), than $f(x)=+-n$ , ...

We can say:

$|4/3x+7|=9rArr4/3x+7=+-9rArr4/3x=-7+-9rArr$

$x=3/4(-7+-9)rArr$

$x_1=3/4(-7-9)=3/4*(-16)=-12$

$x_2=3/4(-7+9)=3/4*2=3/2.$

How do you solve abs(4/3x+7)+5=14abs(4/3x+7)+5=14?