How do you solve # abs(4x - 2) = 10 #?
1 Answer
Aug 8, 2015
Explanation:
You're dealing with an absolute value equation, which means that you need to take into account two possibilities for the modulus
- if
#4x-2>=0# , you have
#|4x-2| = 4x-2#
and the equation becomes
- If
#4x-2<0# , then you have
#|4x-2| = -(4x-2) = -4x+2#
and the equation becomes
So, your equation has two possible solutions: