How do you solve abs((4x-2)/5)=abs((6x+3)/2)?

1 Answer
Jan 22, 2017

-11/38 and -19/22. The values are zeros ( y = 0 ), in the Socratic graph.

Explanation:

It is |2x-1|=3.75|2x+1|. Breaking up,

2x-1=3.75(2x+1), when x > 1/2,

giving extraneous x = -19/22,

-(2x-1)=3.75(2x+1), when -1/2< x < 1/2,

giving x = -11/38 in (-1/2, 1/2) and

-(2x-1)=-3.75(2x+1), when x < -1/2,

giving x = -19/22 < -1/2.

graph{|x-1|-2.5|2x+1| [-1, 0, -3.075, 2.075]}