How do you solve $| 4 y - 15 | = 13$ $abs(4y-15)=13$ ?

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Answer 1 · 2018-06-01T22:21:18

$y = 7, \frac{1}{2}$ $y=7,1/2$

Equations of the form $| x | = b$ $|x|=b$ can be rewritten as $x = \pm b$ $x=+-b$ .

The absolute value bars go away, and we'll have two equations:

$4 y - 15 = 13$ $4y-15=13$ and $4 y - 15 = - 13$ $4y-15=-13$

Solving the first one, we get

$4 y = 28$ $4y=28$

$y = 7$ $color(blue)(y=7)$

Solving the second, we get

$4 y = 2$ $4y=2$

$y = \frac{1}{2}$ $color(blue)(y=1/2)$

Our solutions are in blue.

Hope this helps!

How do you solve |4y−15|=13abs(4y-15)=13?