How do you solve abs(5-2x)=13?

1 Answer
Mar 2, 2018

x=-4" or "x=9

Explanation:

"the value inside the "color(blue)"absolute value bars "" can be"
"positive or negative "

rArr"there are 2 possible solutions"

5-2x=13larrcolor(red)"positive inside bars"

"subtract 5 from both sides"

cancel(5)cancel(-5)-2x=13-5

rArr-2x=8

"divide both sides by "-2

(cancel(-2) x)/cancel(-2)=8/(-2)

rArrx=-4larrcolor(blue)"first solution"

-(5-2x)=13larrcolor(red)"negative inside bars"

rArr-5+2x=13

"add 5 to both sides"

cancel(-5)cancel(+5)+2x=13+5

rArr2x=18

"divide both sides by 2"

(cancel(2) x)/cancel(2)=18/2

rArrx=9larrcolor(blue)"second solution"

color(blue)"As a check"

"Substitute these 2 possible solutions into the left side"
"of the equation and if equal to right side then they are"
"the solutions"

x=-4rArr|5+8|=|13|=13larr" True"

x=9rArr|5-18|=|=13|=13larr" True"

rArrx=-4" or "x=9" are the solutions"