How do you solve $| 8 - 2 n | = 2$ $abs(8-2n)=2$ ?

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Answer 1 · 2018-03-22T16:00:36

$n$ $n$ can be either 3 or 5

$8 - 2 n$ $8-2n$ can be either 2 or -2

If $8 - 2 n = 2 \Rightarrow n = 3$ $8-2n = 2 => n = 3$

If $8 - 2 n = - 2 \Rightarrow n = 5$ $8-2n = -2 => n = 5$

$n$ $n$ can be either 3 or 5

How do you solve abs(8-2n)=2|8−2n|=2abs(8-2n)=2?