How do you solve $| 8 - 6 c | = 1$ $abs(8 - 6c ) = 1$ ?

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Answer 1 · 2017-02-19T11:42:46

$\frac{7}{6} \leq c \leq \frac{3}{2}$ $7/6<=c<=3/2$

The given equation is equivalent to:

$- 1 \leq 8 - 6 c \leq 1$ $-1<=8-6c<=1$

Let's subtract 8 and get:

$- 9 \leq - 6 c \leq - 7$ $-9<=-6c<=-7$

then change signs and inequality:

$7 \leq 6 c \leq 9$ $7<=6c<=9$

and divide all terms by 6:

$7/6<=c<=cancel9^3/cancel6^2$

$7/6<=c<=3/2$

How do you solve abs(8 - 6c ) = 1|8−6c|=1 abs(8 - 6c ) = 1?