How do you solve $abs(k-10)=3$ ?

Question

2350 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-25T17:02:19

$k = 7, k = 13$

$|k-10| = 3$ is really two problems:

$+(k-10) = 3$ and $-(k-10) = 3$

Solve each one:
$k - 10 = 3$
$k -10 + 10 = 10 + 3$
$k = 13$

$-(k-10) = 3$
$-k+10 = 3$
$-k+10-10 = 3-10$
$-k = -7$
$k = 7$

How do you solve abs(k-10)=3abs(k-10)=3?