How do you solve $∣ ∣ ∣ x + \frac{1}{3} ∣ ∣ ∣ = \frac{5}{3}$ $abs(x+ 1/3)=5/3$ ?

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How do you solve $∣ ∣ ∣ x + \frac{1}{3} ∣ ∣ ∣ = \frac{5}{3}$ $abs(x+ 1/3)=5/3$ ?

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Answer 1 · 2018-05-28T03:27:04

$x = \frac{4}{3}$ $x = \frac{4}{3}$ , $x = - 2$ $x =-2$

Explanation:

Since $∣ ∣ ∣ x + \frac{1}{3} ∣ ∣ ∣ = \frac{5}{3}$ $|x+\frac{1}{3}| = \frac{5}{3}$ ,
$\pm (x + \frac{1}{3}) = \frac{5}{3}$ $\pm (x+\frac{1}{3}) = \frac{5}{3}$
$x + \frac{1}{3} = \frac{5}{3}, x + \frac{1}{3} = - \frac{5}{3}$ $x+\frac{1}{3} = 5/3, x+\frac{1}{3} = -5/3$
$x = \frac{4}{3}, x = - \frac{6}{3} = - 2$ $x = 4/3, x = -6/3 = -2$

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How do you solve $∣ ∣ ∣ x + \frac{1}{3} ∣ ∣ ∣ = \frac{5}{3}$ $abs(x+ 1/3)=5/3$ ?

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