How do you solve $| x - 2 | + 10 = 12$ $abs(x-2) + 10 = 12$ ?

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Answer 1 · 2015-07-07T15:25:32

$x \in {0, 4}$ $x \in {0, 4}$

$| x - 2 | = 2$ $|x - 2| = 2$

$| y | = 2 \Rightarrow y = \pm 2$ $|y| = 2 \Rightarrow y = ± 2$

$x - 2 = 2$ $x - 2 = 2$ or $x - 2 = - 2$ $x-2 = -2$

$x = 4$ $x = 4$ or $x = 0$ $x = 0$

How do you solve |x−2|+10=12abs(x-2) + 10 = 12?