How do you solve abs(x^2+6x)= 3x+18x2+6x=3x+18?

1 Answer
Jun 8, 2018

x_1=x_2=-6x1=x2=6, x_3=-3x3=3 and x_4=3x4=3

Explanation:

|x^2+6x|=3x+18x2+6x=3x+18

(x^2+6x)^2=(3x+18)^2(x2+6x)2=(3x+18)2

(x*(x+6))^2=(3*(x+6))^2(x(x+6))2=(3(x+6))2

x^2*(x+6)^2=9*(x+6)^2x2(x+6)2=9(x+6)2

(x^2-9)*(x+6)^2=0(x29)(x+6)2=0

(x+6)^2(x+3)(x-3)=0(x+6)2(x+3)(x3)=0

So x_1=x_2=-6x1=x2=6, x_3=-3x3=3 and x_4=3x4=3